How to Calculate the Amount of Concrete Needed for Different Size Stone Molds

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The question was, how much concrete do I need and what does it cost for different sized stone molds?

Obviously, you cannot be "exact" as there are too many variables, like the thickness variables, the water content in the batch, the dry volume discrepancy in the mix when it is made, etc., etc.  But using the "base cubic yield" of a standard batch, you can come pretty close in estimating your yield and thus raw material needs.

We already know that all things being perfect, the yield of each full batch is 3.6 cubic feet (rounded) of mix, or 6221 cubic inches.  All you need do is estimate how many individual stones or tiles you can get from that, based on the area and thickness (cube) of each stone being poured. As an example, let's say that you have purchased a set of our Olde Appalachian Fieldstone molds.  Each sheet (or set) will cover an estimated seven square feet of area.  That number includes all of the grout, or mortar lines around each stone.  So let's say that the actual "stone" by itself, covers six square feet of area.  And let's say that you are pouring them to the full average thickness of 1.5" thick. You would multiply the full area covered (6 sq. ft.), by 144 to get the square inches (864), then again by the average thickness (1.5"), to get the cubic inch volume of stone being made from that one set.  That total is 1296 cubic inches. Now divide that number into the batch yield of 6221 cubic inches of concrete, and you see that you can fill 4.8 sheets of this particular style of stone with a full batch of concrete.  This yields coverage of about 33.6 square feet of stone coverage per batch.

You can use this same basic logic or formula to figure raw materials needed for almost any project.  As an example... if you had a wall that was 10'x10' = 100 square feet of area.  And you wanted to cover it with Olde Appalachian Fieldstone.  Using the above figures, you would need to purchase enough material to make three full batches of concrete... 33.6 X 3 = 100.8 sq. ft.

NOTE: IF YOU WERE USING JUST ONE SET OF MOLDS, YOU WOULD NEED TO MAKE A 20% BATCH SIZE SINCE A FULL BATCH WILL FILL ABOUT FIVE SETS (SHEETS) OF THIS STYLE OF MOLDS.    

How Many Molds Will an 80 lb. Bag of Premix Fill?

To figure the number of molds that can be filled with an 80 lb. bag of premix, just keep in mind that an 80 lb. bag makes .6 cubic feet of concrete... that would be about 12 half-inch thick 12"x12" tiles.  The formula is as follows, and can be adjusted for whatever size molds you are trying to figure.  To get one cubic foot of concrete, you multiply 12x12x12 which equals 1728 square inches. 

To get the approximate yield from the 80 lb. bag of premix concrete, you multiply the 1728 square inches times .6 (cubic feet) which equals 1036.8 cubic inches.  To see how many 12"x12"x1/2" tiles you can make from that bag of concrete, you divide the total of 12x12x.5 which equals 72 square inches. (12x12x.5 = 72).  Now divide that into the 1036.8, which is .6 cubic feet and you end up with 14.4 tiles.  That's over 14 square feet of tile for an under $4.00 bag of concrete!  If you were using Portland and bulk sand, your cost would be a fraction of that.

Let's say you wanted to know how many 6"x6"x2.5" Pavers, (our #P-662 Paver), you can get from an 80 lb. bag of premix.  Figure your cubic inches to fill one mold... 6x6x2.5=  90 cubic inches to fill one 6x6x2.5" mold.  Divide that into the 1036.8 cubic inch yield per bag, and you get about 11 and a half P-662 Pavers per 80 lb. bag of premix concrete.

An 18"x18"x1.5" Castle Stone Stepping Stone?  Again... 18x18x1.5 = 486 cubic inches.  Divide that into 1036.8 and you get 2.13 stepping stones per bag.   That may or may not seem like that much of a yield from a bag of concrete, but keep in mind that an 18x18 steppingstone covers 2.25 square feet of area.  So you are getting over 4.5 square feet of area covered with a 1.5" thick steppingstone for about a $4.00 bag of concrete.  You are well under $1.00 per square foot in this case.

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